A farmer moves along the
of side 10m in 400s. What is the
- displacement of the farmer
seconds from his own initial
boundary of a square field
will be the magnitude of
at the end of 2 minutes 20s of its
position?
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Answer:
10× (2) ½
Explanation:
Total distance covered 10m in 40sec
Total time taken= 2min 20sec= 140sec
Total round completed = 140/40=3.5 rounds
So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.
AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200
AC = (200)1/2
AC= 10× (2) ½
Note : I have taken completion of 10m side in 40s as one person cannot take 400s to move 10m distance.
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