Question

A farmer moves through a square field of side 10m in 40s m . What will be the magnitude of displacement of the farmer at the end of 2 min 20 sec

Answer 1

$\bf\large\underline\pink{Solution}$

$\large\underline\green{Hi friend!!!}$

Total distance covered 10m in 40sec

Total time taken= 2min 20sec= 140sec

Total round completed = 140/40=3.5 rounds

So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.

AC2= AB2 +BC2 

AC2= (10)2 +(10)2

AC2= 100+100

AC2=200

AC = (200)1/2

 

$\bf\small\underline\blue{AC= 10× (2) ½...}$

Answer 2

➹The magnitude of displacement will be ✤10√2 metres. ✤➷

REFER TO THE ATTACHMENT FOR EXPLANATION