Math, asked by bbrianalimaa, 5 hours ago

A farmer rotates wheat, corn, and soybean crops on her farm1. The farmer produces 293 bushels of produce and sells them for a total of $1,557. Wheat costs $8 for a bushel. Corn costs $4 a bushel. Soybeans cost $9 a bushel. If the farmer's crops yield 4.75 times more corn than wheat, how many bushels of each crop does the farmer produce?

Answers

Answered by jaiswalkshitij456
24

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Answered by amitnrw
1

Given :  A farmer rotates wheat, corn, and soybean crops on her farm1. The farmer produces 293 bushels of produce and sells them for a total of $1,557. Wheat costs $8 for a bushel. Corn costs $4 a bushel. Soybeans cost $9 a bushel. If the farmer's crops yield 4.75 times more corn than wheat,

To Find :  how many bushels of each crop does the farmer produce?

Solution:

W + C  + S   = 293

8W + 4C + 9S  = 1557

C = 4.75W

Substitute C = 4.75W  in  first two equations

=> 5.75W  + S = 293

   27W + 9S  = 1557  => 3W  + S  = 173

=> 2.75W  = 120

=> W = 120/2.75  = 24/0.55  = 2400/55  = 480/11  

C = 4.75W  = 2280/11

480/11 + 2280/11 + S = 293

=> S = 463/11

bushels of each crop does the farmer produce

Corn = 2280/11

Wheat = 480/11  

Soya = 463/11

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