Question

A farmer runs a pipe of internal diameter 20 cm from the canal into a cylindrical tank in his field which is 10 m in diameter and 2 m deep. If water flows through the pipe at the rate of 3 $\frac{km}{h}$ , in how much time will the tank be filled?

Answer 1

Answer:

In 100 min or  1 hr 40 min the tank will be filled.  

Step-by-step explanation:

Given :  

Diameter of a canal  = 20 cm

Radius of a canal , R = 20/2 = 10 cm = 10/100 = 1/10 m

Diameter of a cylindrical tank  = 10 m

Radius of a cylindrical tank , r = 10/2 = 5 m

Height of a cylindrical tank , h = 2 m

Speed of flow of water = 3 km/h  

= 3 × 1000 m/h = 3000 m/h  

[1 km = 1000 m]  

Length of water flows in 1 hour , l = 3000 m  

Area of pipe which is in the form of circle = πR²

= π(1/10)² = π/100 m²

Area of pipe = π/100 m²

Volume of cylindrical tank  = πr²h = π(5)² × 2

= π × 25 ×  2 = 50π m³

Volume of cylindrical tank = 50π m³

Required time = Volume of cylindrical tank / Area of pipe × Length of water

= 50π / (π/100 × 3000) h  

= (50 × 60 × 100) / 3000 min  

= 300000/3000 = 100 min  

Required time = 100 min = 1 hr 40 min

Hence, in 100 min or 1 hr 40 min the tank will be filled.  

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

here's your ans !!!!!!

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