Question

a farmer sell two Buffalo for rs 20000 each if one he gain 20% and other loses 20%find his net gain or loss on whole transaction​

Answer 1

Solution→

☆ if a person sells two commodity at same price on one he gains X percentage and other He losses X percentage then as a whole he will be in a loss and the loss percentage will be equal to →

$(\frac{common \: gain \: or \: loss ^{2} \: }{ {10}^{2} } )$

So here according to the given question :-

Common gain and loss % = 20 %

Then overall loss percentage :-

$= > \frac{ ( {20)}^{2} }{( {10)}^{2} }$

$= > \frac{400}{100}$

Then loss percentage =. 4%

Overall S.P = 20000 + 20000 = rs 40000

Now Overall C.P =

$\frac{100 \times 40000}{100 - 4}$

$= > 41666.67$

C.P = 41,666.67

S.P = 40,000

Then Loss = C.P - S.P

Loss = 41666.67 - 40000

So, Loss is rs 1666.67 .

Answer 2

SOLUTION:-

Given:

A farmer sells two Buffalo for Rs.20000, each he gain 20% & other loss 20%.

To find:

The net gain or loss on whole transaction.

Explanation:

We have,

Two Buffalo for Rs.20000

For 1st buffalo:

A farmer sell Rs.20000.

He gain= 20%

Using formula of the percentage of cost price:

$C.P. = ( \frac{100}{100 + gain} ) \times sp$

So,

$C.P.= ( \frac{100}{100 + 20} ) \times Rs.20000 \\ \\ C.P. = Rs.\frac{100}{120} \times 20000 \\ \\ C.P. = Rs. \frac{200000}{12} \\ \\ C.P. = Rs.16666.66$

&

For 2nd Buffalo:

Selling price= Rs.20000

Loss= 20%

Using Formula:

$C.P. = ( \frac{100}{100 - loss\%} ) \times S.P. \\ \\ C.P. = ( \frac{100}{100 - 20} ) \times rs.20000 \\ \\C.P. = Rs.\frac{100}{80} \times 20000 \\ \\ C.P.= Rs. \frac{200000}{8} \\ \\ C.P. = Rs.25000$

Now,

Overall S.P.= Rs.2×20000

Overall S.P.= Rs.40000.

&

Overall C.P.= Rs.16666.66 + Rs.25000

Overall C.P. = Rs.41666.66.

Now,

Cost price > Selling price

Overall loss= Rs.[41666.66 - 40000]

Overall loss= Rs.1666.66.