Math, asked by Shuhana, 1 year ago

A farmer sold 2 bullocks for 24000 each . 1 bullock he gained 25% and the other he lost 20%. find loss or profit percentage

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Answers

Answered by rohitkumargupta
322

Total Selling Price for 2 bullocks = 24000 + 24000 = 48000.

Given that, on the 1st bullock, he gains 25%.

Cost Price of the 1st bullock
= 24000 * 100/125

 = 19200.


Given that, on the 2nd bullock, he lost 20%.

Cost price of the 2nd bullock
= 24000 * 100/80

= 30000.


Total cost price of 2 bullocks
= 19200 + 30000

= 49200.


We know that Loss = CP - SP

                                  = 49200 - 48000

                                  = 1200.


AND,

Loss% = (Loss/CP) * 100

 = (1200 * 100/49200)

= 2.43%


Hope this helps this help you......,

Answered by veerabhadrakumpatla
153

1st bullock

Sp=24000

Gain=25%

Cp=sp×100/100+gain

=24000×100/100+25

=19200

2nd bullock

Sp=24000

Loss=20%

Cp=sp×100/100-loss

=24000×100/100-20

=30000


Now,

Total sp=24000+24000

=48000

Total cp=19200+30000

=49200

Cp is greater than Sp

So,

We got loss

Loss =cp-sp

=49200-48000

Loss =1200

Then

Loss% = loss/cp×100

=1200/49200×100

= 2.4390

=2.44

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