Math, asked by hammadmakhdoomp4560, 1 year ago

A farmer sold 2 bullocks for $24000 each. On one Bullock he gained 25%and on the other he lost 20% find his total profit or loss percentage?

Answers

Answered by anjlena
6

cp1 = 24000

cp2 = 24000

sp1 = cp × (100+profit)/100

= 24000×125/100

=28800

sp2 = cp × (100-loss)/100

=24000 × 80 /100

=19200

total cp = 24000+24000

=48000

total sp = 28800+19200

=48000

=> no profit no loss

Answered by Anonymous
2

Answer:   2.43%

Explanation:

On 1st Bullock He gains 25%,

                     Therefore,

                       Cost Price of the 1st bullock

                     = 24000 * 100/125

                     = 19200

On 2nd Bullock He lost 20%

                                 Cost price of second Bullock

                           = 24000 * 100/80

                           = 30000

Total Selling Price for 2 bullocks

                                          = 24000 + 24000

                                          = 48000

 Total cost price of 2 bullocks

                                        = 19200 + 30000

                                        = 49200

We know that,

                                   Loss = CP - SP

                                = 49200 - 48000

                                = 1200.

We know that,

                                    Loss% = (Loss/CP) * 100

                                  = (1200 * 100/49200)

                                  = 2.43%

Therefore, Total loss percent of Farmer is 2.43%

Explanation:

In this question, There are given 2 Bullocks which were sold for 24000 each.

On 1 Bullock He gains 25% And,

On 2nd Bullock He lost 20%

                  

So, First we find the cost price of 1st and 2nd Bullock. Which is 19200 and 30000

And, Later we find the total selling price of 2 Bullocks, which we get 48000.

We do, Loss = C.P - S.P

We get 1200

After that, we get Lost percent as 2.43%

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