Math, asked by lucky432, 1 year ago

A farmer sold 2 bullocks for rs 24000 each. on one Bullock he gained 25% and on the other he lost 20%.find his total profit or loss percent?

Answers

Answered by abhilasha21290pdk2jb
8
herw is answer!!!!!!!!!!!!!!!
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Answered by tnwramit1
6
Given
Selling price of bullock =₹24000

On one he got 25% gain

On other he got 20% loss

Now let first of all we will calculate the cost prices of both the bullocks

For 25% profit

cp = sp \times  \frac{100}{100 + profit}
cp = 24000 \frac{100}{100 + 25}

cp = 24000 \times  \frac{100}{125}

cp = 24000  \times  \frac{4}{5}

Cp=19200

Cost price of first bullock =19200

Cp of 2nd bullock

Cp=sp x (100/100-loss)

Cp=24000x(100/100-20)

Cp=24000x100/80

Cp=24000x10/8

Cp=3000x10

Cp=30000

Cp of 2nd bullock =30000

Total cp =30000+19200

=49200

Total sp =24000+24000

=48000

Cp>sp=loss

Loss=49200-48000

=1200

Loss%= (loss/cp) x 100

=(1200/48000) x 100

=120/48

=10/4

LOSS%=2.5%

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