A farmer sold 2 bullocks for rs24000 each.On 1 bullock he gained 25% and on other he lost 20%. Find his total profit or loss percent
Answers
SP of 2 Bullock's = ₹24000
Gain at 1st Bullock = 25%
CP of 1st Bullock = SP * 100/ 100 + G%
=> 24000 * 100/ 100 + 25%
=> 24000 * 100/ 125
=> ₹19200
Loss at 2nd Bullock = 20%
CP of 2nd Bullock = SP * 100/100 - L%
=> 24000 * 100/ 100 - 20%
=> 24000 * 100/ 80
=> ₹30000
Total CP = 19200 + 30000
=> ₹49200
Total SP = ₹24000 * 2
=> ₹48000
Thus, Loss
Loss = CP - SP
=> 49200 - 48000
=> ₹1200
Loss% = Loss * 100/ CP
=> 1200 * 100 / 49200
=> 2.43%
_______________
If it is correct mark me brainlest and follow me too..
_______________
Answer: 2.43%
Explanation:
On 1st Bullock He gains 25%,
Therefore,
Cost Price of the 1st bullock
= 24000 * 100/125
= 19200
On 2nd Bullock He lost 20%
Cost price of second Bullock
= 24000 * 100/80
= 30000
Total Selling Price for 2 bullocks
= 24000 + 24000
= 48000
Total cost price of 2 bullocks
= 19200 + 30000
= 49200
We know that,
Loss = CP - SP
= 49200 - 48000
= 1200.
We know that,
Loss% = (Loss/CP) * 100
= (1200 * 100/49200)
= 2.43%
Therefore, Total loss percent of Farmer is 2.43%
Explanation:
In this question, There are given 2 Bullocks which were sold for 24000 each.
On 1 Bullock He gains 25% And,
On 2nd Bullock He lost 20%
So, First we find the cost price of 1st and 2nd Bullock. Which is 19200 and 30000
And, Later we find the total selling price of 2 Bullocks, which we get 48000.
We do, Loss = C.P - S.P
We get 1200
After that, we get Lost percent as 2.43%