Question

a farmer sold 2bullocks for 20000 each an one bullocks he gained 25% and on the other he lost 20%find his total profit or loss precent​

Answer 1

Answer :-

The loss percentage of the farmer is 5%.

Step-by-step explanation

To Find :-

• The total profit or loss percentage.

★ Solution

Given,

• Amount of two bullocks a farmer sold = Rs. 20,000
• One he gained = 25%
• Other he lost = 20%

For one bullock :

S.P. = Rs. 20,000 and Gain = 25%

Therefore, Cost Price

As we know that,

Cost price = 100/(100 + gain%) × S.P.

A.T.Q,

→ 100/(100 + gain%) × S.P

→ 100/(100 + 25) × 20000

→ 100/125 × 20000

→ 2000000/125

→ Rs. 16,000

Now, For other bullock :

S.P. = Rs. 20,000 and Loss = 20%

Therefore, Cost Price

As we know that,

Cost price = 100/(100 - loss%) × S.P.

A.T.Q,

→ 100/(100 - loss%) × S.P.

→ 100/(100 - 20) × 20000

→ 100/80 × 20000

→ 2000000/80

→ Rs. 25000

Now, Total C.P. and S.P. of bullocks :-

Total C.P. of two bullocks

→ Rs. (16,000 + 25,000)

→ Rs. 41,000

Total S.P. of two bullocks

→ Rs. (20,000 + 20,000)

→ Rs. 40,000

As Cost price is greater than Selling price

So, Loss

→ C.P. - S.P.

→ Rs. (41,000 - 40,000)

→ Rs. 1,000 = Loss

By the problem,

• The loss percentage :-

→ Loss% = Loss/C.P. × 100

→ 1000/20000 × 100

→ 100000/20000

→ 10000/2000

→ 1000/200

→ 100/20

→ 10/2

→ 5% = Loss percentage.

Hence, The loss percentage is 5%.

Answer 2

Answer:

Total Selling Price for 2 bullocks = $\underline\pink{24000 + 24000 = 48000.}$

Given that, on the 1st bullock, he gains 25%.

Cost Price of the 1st bullock = $\underline\red{\frac{ {24000}^{100} }{125} = 19200.}$

$\large\bf \underline\purple{Given \: \: that, }$

on the 2nd bullock, he lost 20%

Cost price of the 2nd bullock = $\underline\pink{\frac{{24000}^{100} }{80} = 30000.}$

Total cost price of 2 bullocks

$\small\bf\red{= 19200 + 30000}$

$\large\underline\red{ = 49200.}$

We know that Loss CP-SP

= 49200 - 48000

= 1200.

AND,

Loss%= $\small\bf\pink{ { \frac{Loss}{CP} }^{100} }</p><p>$

= (1200*100/49200)

= 2.43%