Question

A farmer sold 3/5 of his chicken. If he had 30 chickens left, how many chickens had he at first? A. 75
B. 65
C. 55
D. 45

Answer 1

Answer:

A. 75

Step-by-step explanation:

A farmer sold 3/5 of his chicken and 2/5 left

let total no. of chicken be x

2/5 of x= 30

X=30×5. =. 75

2

Answer 2

Given: Number of chickens sold by the farmer = $\frac{3}{5}$ of chickens he had in the beginning

          Number of chickens left = 30

To find: The number of chickens he had in the beginning

Let: The number of chickens he had at first be $x$

Solution: According to the given question and assumption made,

Number of chickens, the farmer had in the beginning = $x$

Number of chickens he sold = $\frac{3}{5}x$

Number of chickens left = 30

∵ Number of chickens left = Number of chickens in the beginning - Number of chickens sold

⇒ $30 = x - \frac{3}{5}x$

⇒ $30 = \frac{5x \ - \ 3x}{5}$

⇒ $2x = 30*5 = 150$

⇒ $x = \frac{150}{2} = 75$

Hence, the farmer had 75 chickens at first.