Math, asked by kushagrashukla89, 11 months ago


A farmer sold a call and a cow for 760. Mereby making a profit of 25% on the calf and 10% on
the cow Ry selling them for 767 50, he would have realised a profit of 10% on the calf and 25%
on the cow Find the cost of each

Answers

Answered by Blaezii
10

Answer:

350 is your answer.

Step-by-step explanation:

Given Problem:

A farmer sold a call and a cow for 760. Mereby making a profit of 25% on the calf and 10% on  the cow Ry selling them for 767 50, he would have realised a profit of 10% on the calf and 25%  on the cow Find the cost of each.

Solution:

Let C.P. of a calf be Rs 'x' and C.P. of a cow be Rs 'y'.

Now according to the question;

125x/100 + 110y/100 = 760 ..............(1)

110x/100 + 125y/100 = 767.50 ..............(2)

Now by solving (1) and (2), we get,

x = 300 and y = 350

Therefore,

The cost of calf is Rs 300.

The cost of cow is Rs 350.

Similar questions