A Farmer sold two bullocks at Rs.18000 for each. He loses 20% on first bullocks and gained 20%. Find the gain or loss percent
Answers
First case,
Let CP be x.
Loss = 20%
SP = x - 20% of x = 18000
i.e. x = 18000*100/80 = Rs 22,500.
Second case,
Let CP be x .
Gain = 20%
SP = x + 20% of x = 18000
i.e. x = 18000*100/120 = Rs 15,000
Total CP = 22500+15000 = Rs 37500.
Total SP = 18000*2 =Rs 36000.
So, Loss = Rs (37500-36000) = Rs 1500.
Loss % = 1500*100/37500 = 4.
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Step-by-step explanation:
SOLUTION -
SP of the bullock = rs 18000
Gain = 20 %
CP of the first bullock
= ( \dfrac{100}{100 + gain\%}) \times sp(
100+gain%
100
)×sp
★ CP of the first bullock
= ( \dfrac{100}{100 + 20}) \times 18000(
100+20
100
)×18000
= \dfrac{100}{120} \times 18000 = rs15000=
120
100
×18000=rs15000
SP of the second bullock = rs 18000
Loss = 20%
CP of the second bullock = ( \dfrac{100}{100 \times loss\%}) \times sp(
100×loss%
100
)×sp
★ CP of the second bullock
=( \dfrac{100}{100 - 20}) \times 18000(
100−20
100
)×18000
= \dfrac{100}{80} \times 18000 = rs22500=
80
100
×18000=rs22500
Total cost price of the two bullocks
= rs 15000 + rs 22500 = rs 37500
Total selling price of the two bullock
= 2 × 18000 = rs 36000
Loss = CP - SP
= rs 37500 - 36000 = rs 1500
hence , the farmer suffers the loss of rs 1500.