Math, asked by zajeeshz537, 1 year ago

A farmer sold two bullocks for rs24000 each.On 1bullock he gained 25%and on the other he lost 20%.Find his total profit or loss percent

Answers

Answered by kdevi8634
4

SP of 1 bull = 24000

P = 25 %

P = 25/100*24000

P = 6000

CP = SP - P

24000 - 6000 = 18000

SP of 2 bull = 24000

L = 20 %

L = 20/100*24000 = 4800

CP = SP + L

24000 + 4800 = 28800

Total SP =48000

Total CP = 46800

L = 2800

L % = L/CP*100

2800/46800*100 = 6 %


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Answered by Anonymous
1

Answer:   2.43%

Explanation:

On 1st Bullock He gains 25%,

                     Therefore,

                       Cost Price of the 1st bullock

                     = 24000 * 100/125

                     = 19200

On 2nd Bullock He lost 20%

                                 Cost price of second Bullock

                           = 24000 * 100/80

                           = 30000

Total Selling Price for 2 bullocks

                                          = 24000 + 24000

                                          = 48000

 Total cost price of 2 bullocks

                                        = 19200 + 30000

                                        = 49200

We know that,

                                   Loss = CP - SP

                                = 49200 - 48000

                                = 1200.

We know that,

                                    Loss% = (Loss/CP) * 100

                                  = (1200 * 100/49200)

                                  = 2.43%

Therefore, Total loss percent of Farmer is 2.43%

Explanation:

In this question, There are given 2 Bullocks which were sold for 24000 each.

On 1 Bullock He gains 25% And,

On 2nd Bullock He lost 20%

                  

So, First we find the cost price of 1st and 2nd Bullock. Which is 19200 and 30000

And, Later we find the total selling price of 2 Bullocks, which we get 48000.

We do, Loss = C.P - S.P

We get 1200

After that, we get Lost percent as 2.43%

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