Question

A farmer thought of dividing the triangular plot ABC between his son and a daughter. A(4,-6), B(3, -2) and C(5, 2) are the vertices of that triangular plot. He drew a line AD in such a way that D is the mid-point of BC. Prove that the line AD divides the plot into two smaller triangular pieces of equal area. What values of farmer are depicted by this division?

Answer 1

According to question

Vertices of triangular Plot

A = (4, -6)
B = (3, -2)
C = (5, 2)
Also
D is the mid point on BC
Thus
Coordinates of D = [ 3+5 / 2,  -2+2 / 2 ]
                            = [ 4, 0 ]
Thus
D = (4, 0)
Now Area of traingle
Area of triangle ABD = 1/2 [ -1 * 6  -  0 * 4 ]
                                 = 1/2 * -6
                                  = -3
Area of triangle ACD = 1/2 [ 1* 6 -  0 * 8 ]
                                   = 3

Answer 2

hey mate here is ur answer in photo pls mark as brainlist if it helps u and pls follow me if u like