Question

A farmer walked a total of 64 km and spent a total of 18 hours walking in two days.

On the second day, the farmer walked 2 hours longer and one km per hour faster than he walked on the first day.

Then, what was his speed on the first day?

Answer 1

Step-by-step explanation:

Given A farmer walked a total of 64 km and spent a total of 18 hours walking in two days. On the second day, the farmer walked 2 hours longer and one km per hour faster than he walked on the first day.

Then, what was his speed on the first day?

• So the farmer has walked for two hours.
• Let the first day be m hours (farmer walked)
• So the next day will be m + 2 hours
• So we get  
•             m + m + 2 = 18
•                   2m = 18 – 2
•                    2m = 16
•                        Or m = 8 hours
• So the farmer walks 8 hours on first day and  
•                 m + 2 = 8 + 2 = 10 hours on the next day  
• Now let the average speed of the farmer be x km / hour
• Next day the average speed will be x + 1 km /hour
• Therefore total distance covered will be
•                        8x + 10 (x + 1) = 64
•                        8x + 10 x + 10 = 64
•                               18 x = 64 – 10
•                                  18 x = 54
•                                  Or x = 3 km /hour  

Therefore the average speed on the first day will be 3 km/hr

Reference link will be

https://brainly.in/question/48086465