Question

A farmer wants to fence his rectangular field 28 m x 49 m with wire. He wants to spend minimum amount in fixing the pillars for wire at equal distance. If
cost of focing one pillar is Rs 1000, then total cost of fixing pillars will be:



I will give 20 points.

And will give brainliest ASAP

Pls answer fast

Answer 1

Answer:

=27600 rupees.

Step-by-step explanation:

Amount of wire required= 3 times the perimeter of field

=3[2(l+b)]

=3(2*230)

=3(460)

=1380 m

so cost will be

1380*20

=27600 rupees.

Answer 2

Answer:

27600 rupees is the answer. hope it helps