A farmer wishes to distribute 153 oranges and 102 guavas into baskets of equal size that
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Dear student
A farmer wishes to distribute 153 oranges and 102 guavas into baskets of equal size that will contain each of the above in equal number.
Oranges = 153 = 3 * 3 * 17
Guavas = 102 = 2 * 3 * 17
HCF = 3 * 17 = 51
Smallest common factor other than 1 = 3
We can have 3 Baskets
Then 51 Oranges + 34 guavas in one basket
Total Fruits in one basket = 51 + 34 = 85
or if we put equal fruits in each basket individually
then 3 basket of 51 oranges
2 baskets of 51 guavas
total 5 Basket
51 fruits in each basket
Regards
H@rsh@l Patil
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