Question

a farmer wishes to fence his field with 3rows of wire. if the dimensions of the field are120m by 68m,find the total length of wire required?

Answer 1

Area of field =l*b
Area! 120*68=8160m2
cost of wire required =8160*3=24480m

Answer 2

Answer:

The total length of wire required be 1128 cm .

Step-by-step explanation:

Formula

Perimeter of the rectangle = 2 (Length + Breadth)

As given

if the dimensions of the field are 120m by 68m .

Length = 120 m

Breadth = 68 m

Putting all the values in the formula

Perimeter of the rectangle = 2 (120 + 68)

                                             = 2 × 188

                                             = 376

As given

A farmer wishes to fence his field with 3 rows of wire.

Total length of the wire required = Number of rows of wire × Perimeter of field .

Total length of the wire required = 3 × 376

                                                      = 1128 cm

Therefore the total length of wire required be 1128 cm .