Question

a farmer wishes to put 39 kg of wheat, 403 kg of oats and 182 kg of barley into the largest bags of equal size that will hold exactly of each kind. how many kgs must each bag hold

Answer 1

The required number of bags will be the HCF.

By prime factorisation,
$403 = 13 \times 31 \\ 182 = 13 \times 2 \times 7 \\ 39 = 13 \times 3$
Therefore HCF is 13.

Now
Wheat = 39/13 =3KG
Oats = 182/13 =14KG
Barley= 403/13 =31KG

Answer 2

Answer:

The required number of bags will be the HCF.

By prime factorisation,

\begin{lgathered}403 = 13 \times 31 \\ 182 = 13 \times 2 \times 7 \\ 39 = 13 \times 3 \\\end{lgathered}403=13×31182=13×2×739=13×3

Therefore HCF is 13.

Now

Wheat = 39/13 =3KG

Oats = 182/13 =14KG

Barley= 403/13 =31KG