Question

A farmers moves along the boundary of a squase field of side 10 m in 40 s. what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position? no spam correct ✅ answer needed no copied​

Answer 1

Answer:

→ Hey Mate,

→ Given Question : A farmers moves along the boundary of a square field of side 10 m in 40 s. what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?​

Explanation:

→  At the end of 2 minutes  20 seconds , the farmer will be at c .

→ Displacement = AC

→  AC² = AB ² + BC²

→         =  10²  + 10²

→         =   100 + 100

→         =  200

→ AB = 300 m

→ AC= 100 m

→ consider an object starting from A and moving along a straight line 300 m to B It then reverses the direction and moves back 200 m to c.

→ Distance AC = AB + BC

→                       = 300 + 200

→               AC        =  500 m

→ Displacement AC = 100 m

→ Distance and Displacement will be equal if an object is traveling in a straight line without reversing its direction.

→ At the end of 2 min 20 sec , the farmer will be at c .

→ Displacement = AC

→ AC² = AB² + BC²

→        = 10² + 10²

→        =  100 + 100

→        =  200

→        =  100 × 2

→  AC      =  √ 100 × 2

→             =  10√ 2

→ THANK YOU

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Answer 2

Answer:

Q. A farmer movers along the boundary of a square field of side 10 m in 40 seconds of shown in the figure below what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds for his initial position?

Answer :

Given, side of the square field = 10 m

Therefore, perimeter = 10×4 = 40 m

Farmer moves along the boundary in 40 s.

Total time of journey = 2×60+20 = 140 s

Since, in 40 s farmer moves 40 m.

Therefore, in 1 s distance covered by farmer = 40/40 m = 1 m

Therefore, in 140 s distance covered by farmer = 10×4 = 40 m

Now,

Number of rotation to cover 140 along the boundary

= (total distance)/(Perimeter)

= 140/40 = 3.5 m

Thus, after 3.5 round farmer will at point C of the field.

Therefore displacement

(AC)² = (10)² + (10)²

(AC)² = 100+100

(AC)² = 200

AC = √200

AC = 14.143 m

• Thus, after 2 minutes 20 seconds the displacement of farmer will be equal to 14.143 m north east.

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