a farmhouse is 27 m long and 23 m wide. how many merets of wire is required for fencing the farm twice
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A farmhouse is 27m long and 23m wide.
So from this statement we can understand that it's rectangular in shape.
To find: How many meters of wire are required for fencing the farmhouse twice.
Procedure:
First find the perimeter of the farmhouse
Perimeter of rectangle= 2×(l+b)
= 2×(27+23)m
= 2× 50m
= 100 m
So length of wire required for fencing the farmhouse once=100m
Length of wire required for fencing the farmhouse twice= 100m×2= 200m
Answer: 200 m
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