Question

A fast moving superfast express crosses another pasenger train in 20 seconds. The speed of faster train is 72 km/hr and speeds of slower train is 27 km/h. Also the length of faster ntrain is 100m, then find the length of the slower train if they are moving in the same direction.

A) 100 m
B) 125 m
C) 150 m
D) 175 m

Answer 1

Answer:

here i change the speed of slower train in m/s and it will be 15/2 m/s and time is given 20 sec and from there i put it in the formula T =D/S from there i got the answer 150 m.

Answer 2

Answer:

The correct answer to this question is $150m$

Step-by-step explanation:

Given - A fast-moving superfast express crosses another passenger train in $20$ seconds. The speed of the faster train in $72$ km/hr and the speed of the slower train is $27$ km/h.

To Find - Find the length of the slower train if they are moving in the same direction.

A fast-moving superfast express crosses another passenger train = $20$ in seconds.

The speed of the faster train in $72$ km/hr

The speed of the slower train in $27$ km/h

Use the formula -

Time  = Sum of the length of the two trains / Difference in speeds

$20 = \frac{(100 + x)}{\frac{25}{2} }$

$x = 150m$

The length of the slower train when they are moving in the same direction is $150m$

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