a fast train cover 320km in 3 hours 20 minutes .How much time will he take to cover a distance of 90km
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Answered by
6
Distance320 km90 kmTime3 hrs 20 min = 10/3 hrs?We know that distance and time are directly proportional
Hence x1/y1 = x2/y2
320/(10/3) = 90/y2
96 y2 = 90
y2 = 90/96 = 15/16 = (15 x 60)/16
Thus y2 = 56 min 25 secs
Hence x1/y1 = x2/y2
320/(10/3) = 90/y2
96 y2 = 90
y2 = 90/96 = 15/16 = (15 x 60)/16
Thus y2 = 56 min 25 secs
Answered by
1
soeed=d/t
=320/(10/3)
=320×3/10
=32×3
=96 km/hr
time=d/s
=90/96 hr
=320/(10/3)
=320×3/10
=32×3
=96 km/hr
time=d/s
=90/96 hr
sujal102:
not right
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