a fast train takes 3 hours less than a slow train for a journey of 600km. if the speed of the slow train is 10kmph less than that of fast train. find the speed of two trains.
Answers
Answer:
Step-by-step explanation:
Let the speed of the fast train be x km/hr
Let the speed of the slow train be (x- 10) km/hr
Hence the time taken by the fast train is 600/x
Time taken by slow train is 600/(x-10)
Therefore (600/x-10) - (600/x) = 3
On reducing we get,
3x^2 -30x-6000 = 0 or x^2 -10x -2000 = 0
On factorising we get x = 50 or -40
The negative value is not acceptable.
Hence x = 50
That is the speed of the fast train is 50km/hr and the speed of the slow train is 40km/hr
Answer:
Step-by-step explanation:Total distance=600 km
speed of slow train=x km/h
speed of fast train=(x+10) km/h
t1(slow) =d/s=600/x hrs
t2(fast)=d/s=600/x+10 hrs
A.T.P
=600/x-600/x+10=3
=600(x=10-x/x(x+10))=3
=2000=x2+10x
=x2+10x-2000=0
=x2+50x-40x-2000=0
=x(x+50)-40(x+50)=0
=(x+50)(x-40)=0
EITHER: OR:
x+50=0 x-40=0
=x=-50 x=40
(hence, speed cannot be in negetive)
so,speed of slow train=40 km/h
speed of fast train=(x+10)km/h
(40+10)km/h
50 km/h