Question

a fast train takes 3 hrs less than a slow train for a journey of 600 km if the speed of slower train is 10 km per hrs less than that of the fast train find the speed of both train

Answer 1

Solution:-

Let the speed of the slow train be 'x' km/hr and the speed of the fast train be (x+10) km/hr.

Time taken by the slow train to cover the distance of 600 km = (600/x) hours

Time taken by the fast train to cover the distance of 600 km = 600/(x+10) hours.

Now, according to the question.

(600/x) - 600/(x+10) = 3

{600(x+10) - 600x}/x(x+10) = 3

600x + 6000 - 600x = 3{x(x+10)}

6000 = 3x² + 30x

3x² + 30x - 6000 = 0 Dividing it by 3 we get

x² + 10x - 2000

x² + 50x - 40x - 2000 = 0

x(x+50) - 40(x+50) = 0

(x-40) (x+50)

x = 40 or x = -50

x = -5 is not possible, the speed cannot be in negative.

So, x = 40

Speed of the slow train is 40 km/hr and the speed of the fast train is 40 + 10 = 50 km/hr.

Answer. 

Answer 2

your answer is 20 samjha tum