a fast train takes 3 hrs. less than a slow train for a journey of 600 Km. If the speed of the slow train is 10 km/hr less than that of the fast train, find the speeds of the two trains
Answers
Answered by
5
Let the speed of the fast train be x km/hr
Let the speed of the slow train be (x- 10) km/hr
Hence the time taken by the fast train is 600/x
Time taken by slow train is 600/(x-10)
Therefore (600/x-10) - (600/x) = 3
On reducing we get,
3x^2 -30x-6000 = 0 or x^2 -10x -2000 = 0
On factorising we get x = 50 or -40
The negative value is not acceptable.
Hence x = 50
That is the speed of the fast train is 50km/hr and the speed of the slow train is 40km/h
Let the speed of the slow train be (x- 10) km/hr
Hence the time taken by the fast train is 600/x
Time taken by slow train is 600/(x-10)
Therefore (600/x-10) - (600/x) = 3
On reducing we get,
3x^2 -30x-6000 = 0 or x^2 -10x -2000 = 0
On factorising we get x = 50 or -40
The negative value is not acceptable.
Hence x = 50
That is the speed of the fast train is 50km/hr and the speed of the slow train is 40km/h
yana85:
hii
f9
Delhi
hii
Answered by
2
Answer:
ur answer is in the ATTACHMENT
Attachments:
Similar questions