Question

A fast train takes one hour less than a slow train for a journey of 200km. If the speed of the slow train is 10km/hr less than that of the fast train, find the speed of the two train.

Fast......

Answer 1

Hey Dear ... ✌️

=) Let speed of fast train be x km/hr

speed of slower train = x - 10 km/hr

A/Q  fast train takes 1 hr less than slower one in covering 200 km

⇒ 200/ x = 200/x-10    -  1

⇒ 200/x = 200 - (x-10) / x-10

⇒ 200(x-10) = 200x - x (x-10)

⇒200x-2000 = 200x - x² + 10x

⇒x² - 10x - 2000 = 0

⇒ x² -50x + 40x -2000 = 0  ⇒ (x-50)(x+40) = 0

x = 50  and x= - 40

since x can't be negative , so x= speed of faster train = 50 km/hr

speed of slower train = 40 km/hr

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