A faster train reaches 2 hrs earlier than a slower train at a destination that is 192 km away. If slower train is 16 kmph slower than the faster train, what is speed of faster train?
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Let the speed of the faster train be x km / h.
∴ Speed of the slower train
= (x - 16) km/h
=> 192/x = (192/x−16) - 2
=> x = 48 km / h
∴ Speed of the slower train
= (x - 16) km/h
=> 192/x = (192/x−16) - 2
=> x = 48 km / h
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