Question

A faster train takes one hour less than a slower train for a journey of 200 km​

Answer 1

Answer:

Time taken by the fast train to cover 200 km = 200/x hr. Time taken by the slow train to cover 200 km = 200/x - 10 hr. Speed of slow train = x - 10 = 50 - 10 = 40 km/h.

Answer 2

Answer:

Let speed of fast train be x km/hr

speed of slower train = x - 10 km/hr

Given fast train takes 1 hr less than slower one in covering 200 km

⇒ 200/ x = 200/x-10 - 1

⇒ 200/x = 200 - (x-10) / x-10

⇒ 200(x-10) = 200x - x (x-10)

⇒200x-2000 = 200x - x² + 10x

⇒x² - 10x - 2000 = 0

⇒ x² -50x + 40x -2000 = 0 ⇒ (x-50)(x+40) = 0

x = 50 and x= - 40

Explanation:

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