Question

A faster train takes one hr less than the a slower train for a journey of 200km/hr . If the speed of slower train is 10km/hr less than that of the faster train . Find the speeds of the trains

Answer 1

Let the speed of faster train be x km/hr.

Speed of slower train = (x-10)km/hr

Time taken by faster train = 200/x hr

Time taken by slower train = 200/(x-10) hr

Given,

200/(x-10)-200/x = 1

Taking LCM of x and x-10

200x-200(x-10) = x(x-10)

200x+2000-200x=x^2-10x

x^2-10x-2000=0

x^2-50x+40x-2000=0

x(x-50)+40(x-50)=0

(x+40)(x-50)=0

x=-40,50

Since speed can't be negative

x=50 km/hr

Speed of faster train= 50 km/hr

Speed of slower train= 40 km/hr

Answer 2

Answer:

Step-by-step explanation: