A fat hose pipe is held horizontally by a fire man. It delivers water through a constricting nozzle of 1lit /s. If by increasing the pressure, the water is delivered at 2lit /s, the fireman has to
Answers
Answer:
filledbookmark
USE APP
Sign in
Questions & Answers
CBSE
Physics
Grade 11
Mechanics of Fluids
Question
Answers
Related Questions
A fat hose pipe is held horizontally by a fireman. It delivers water through a constricting nozzle 1litsec−1 . If by increasing the pressure, the water is delivered at 2litsec−1 , the fireman has to:
A. Push forward
B. Push forward 4 times hard
C. Push forward 8 times hard
D. Push backward 4 times hard
Answer
VerifiedVerified
48.6k+ views
6.3k+ likes
Hint: In order to solve this question, firstly we will find the force due to the initial velocity of water and its mass equivalent to product of density of water and its volume and then we will find force after an increase in pressure and will compare both equations.
Complete step by step answer:
Let us first calculate the initial mass of flowing water which is given as m=ρ×V and initially we have a volume V=1litre
So we get mass m=ρ→(i) (in its respective SI unit)
Now, force F=m×vt
And initial velocity of flowing water is given as v=1litsec−1 and in one second so,
F=m
Or we can write,
F=ρ→(ii)
Now, in final case after increasing the pressure, the new velocity let’s say v′=2litsec−1
Final force say F′=m′v′t
Where m′ is the final mass which is given as of volume two litres
m′=ρ×v′
⇒m′=2ρ Using this we get final force as,
⇒F′=4ρ→(iii)
Now, from equations (ii) and (iii) we can see that,
∴F′=4F
Which means the fireman has to apply force four times forward.
Hence,the correct answer is option B.