Question

A fater is twice as old as daugter If 20 years ago the age of father was 10 times age of the daugter What is the present age of the father?​

Answer 1

Answer:

45 years old

Step-by-step explanation:

Let the present age of daughter = x years

Then present age of father = 2 x years

Age of daughter 20 years ago = (x — 20) years

Age of father 20 years ago = (2x —20) years

According to statement of the problem

2x — 20 = 10 (x — 20)

=> 2x — 20 = 10x — 200

=> 10 x — 2 x = 200 — 20

=> 8 x = 180

=> x = 221/2 years

Present age of daughter = 22½ years

Present age of father = 45 years

Answer 2

Answer:

45 years

Step-by-step explanation:

father's age is 45