Question

a father 24 years older than his son in 7 years the son age will be two fifth of his father age what are their present ages

Answer 1

✬ Father = 33 years ✬

✬ Son = 9 years ✬

Step-by-step explanation:

Given:

• Father is 24 years older than his son.
• After 7 years age of son will be two fifth of his father age.

To Find:

• Present ages of both ?

Solution: Let the present age of son be x years. Therefore,

➟ Father age will be = 24 year more than x

➟ Father age = (x + 24) years

[ After 7 years their ages will be ]

• Son age = (x + 7) years
• Father age = (x + 24 + 7) years

A/q

• After 7 years age of son will be two fifth of his father age.

$\implies{\rm }$ (x + 7) = 2/5(x + 31)

$\implies{\rm }$ x + 7 = 2x + 62/5

$\implies{\rm }$ 5(x + 7) = 2x + 62

$\implies{\rm }$ 5x + 35 = 2x + 62

$\implies{\rm }$ 5x – 2x = 62 – 35

$\implies{\rm }$ 3x = 27

$\implies{\rm }$ x = 27/3

$\implies{\rm }$ x = 9

So, the present age of

• Son age is x = 9 years

• Father age is x + 9 = 24 + 9 = 33 years

Answer 2

AnswEr :-

• Son's age = 9 years
• Father's age = 33 years

Given :-

• A father is 24 years older than his son. In 7 years, the son will be 2/5th of his father's age.

To Find :-

• Present ages of both.

SoluTion :-

Let

• Present age of son be x years
• Father's age will be (x + 24) years

After 7 years :-

• Son's age will be (x + 7) years
• Father's age will be (x + 24 + 7) years

After 7 years, age of son will be 2/5th of his father's age

According to question :-

x + 7 = 2/5 (x + 31)

→ x + 7 = 2x/5 + 62/5

→ x + 7 = (2x + 62)/5

→ 5 (x + 7) = 2x + 62

→ 5x + 35 = 2x + 62

→ 5x - 2x = 62 - 35

→ 3x = 27

→ x = 27/3

→ x = 9

Hence,

• Present age of son = x = 9 years
• Present age of father = (x + 24) = 9 + 24 = 33 years