Question

A father 30 times older than his son. 18 years later , he will be only thrice old as his son. Father's present age?

Answer 1

Heya

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Let the age of son be x and age of father be (30x)

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After 18 years,

Father's age = 30x + 18

Son's age = x + 18 
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According to the given information,

30x + 18 = 3(x + 18) 

30x + 18 = 3x + 54

30x-3x = 54-18 

27x = 36 

x = 36/27 

x = 12/9 = 4/3 


Age of son is $( \frac{4}{3})$ years 

$(\frac{4}{3} ) years = ( \frac{4*12}{3}) months$


Age of son = 4*4 = 16 months 

Age of father =  30 (16) 



Age of father = 480 months 


Age of father = $( \frac{480}{12}) years$

Age of father = 40 years



i hope this will help you



-by ABHAY

Answer 2

Let father ve y years
And son be x years.
So the equations will be
y=30x
3(x+18)=y
Solving these 2 equations...
We will get x=2 and y=60
This implies that father's present age is 60 years..
Hope it help u