Question

A father age is 3 times the sum of ages of 2 childern but after 20 years his age will be equal to the sum of their ages find father present age

Answer 1

Answer:

Let the age of the sons be x and y. Given that Father's age is three times the age of his two sons. Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son. Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.

Answer 2

Answer:

30 years.

Step-by-step explanation:

Let the sum of ages of the two children be "X".

Father's age = 3x

Sum of the ages of the children after 20 years

= X+2(20)

= X+40.

Age of the father after 20 years = 3x +20

According to the problem,

X+40 = 3x +20

x - 3x = 20-40

- 2x = -20

X = -20/-2

X = 10

Therefore, Father's age is 3x = 3(10) = 30 years.