A father age is 3 times the sum of ages of 2 childern but after 20 years his age will be equal to the sum of their ages find father present age
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Answered by
0
Answer:
Let the age of the sons be x and y. Given that Father's age is three times the age of his two sons. Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son. Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.
Answered by
3
Answer:
30 years.
Step-by-step explanation:
Let the sum of ages of the two children be "X".
Father's age = 3x
Sum of the ages of the children after 20 years
= X+2(20)
= X+40.
Age of the father after 20 years = 3x +20
According to the problem,
X+40 = 3x +20
x - 3x = 20-40
- 2x = -20
X = -20/-2
X = 10
Therefore, Father's age is 3x = 3(10) = 30 years.
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