Question

a father age is 5 year less than four times his son age if the father is 35 years old then find the age of his son​

Answer 1

Answer:

Father's age = 35 yrs

Assume, Son's age is X

Therefore,

4 X = 35+ 5

4X = 40

X = 40÷4

X= 10

Age of his son is 10years

Step-by-step explanation:

Father's age is 5 year less than 4 times his son's age means 4 times of son's age is 5yrs more than father's age.

therefore the equation 4 × X = 35 + 5

Answer 2

Answer:

Given: Age of father$=35$ years

Father age is $5$ years less than four times his son age.

To find: Age of son

Solution:

Let age of son $=x$

Age of father $=35$                                       equation 1

According to question, Age of father $(4Xx)-5$                         equation 2

By evaluating equation 1 and 2,

$(4Xx)-5=35\\ 4x-5=35\\ 4x=35+5\\ x=\frac{40}{4} \\ x=10$

Putting value of $x$

Age of son is $10$ years.