Question

A father age is five time is son age 4 years ago the sum of their age is 28.find the present age.​

Answer 1

Answer:

Let son present age = x years

before 4 years he was = (x-4)

A/q, now,

His father age is = 5(x-4)

so,

5(x-4) + x = 28

5x +x = 48

6x = 48

x = 8 years = son age .

Father = 5(x-4) = 5*4 = 20 years .

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Answer 2

Answer:

Step-by-step explanation:

Let son present age = x years

before 4 years he was = (x-4)

A/q, now,

His father age is = 5(x-4)

so,

5(x-4) + x = 28

5x +x = 48

6x = 48

x = 8 years = son age .

Father = 5(x-4) = 5*4 = 20 years .