A father age is three times the sum of the age of his two children after 5 years his age will be two times the sum of their age find the present age of father .
Answers
Answer:
Let the age of father =x years
The sum of the age of 2 children =y years
According to the first condition
⇒x=3y.....eq1
After 5 years
⇒ Father's age =x+5
⇒ The sum of ages of his two children =y+10
According to the second condition
⇒x+5=2(y+10)⇒x+5=2y+20
⇒x−2y=15....eq2
Put the value of x from eq1
⇒3y−2y=15⇒y=15
Put y=15 in eq1
⇒x=3×15⇒x=45
Hence, father age =45 years .
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Answer:
Let the age of two children be x and y So, the father’s present age = 3(x + y) After five years, Age of two children = (x + 5) + (y + 5) years = ( x + y + 10) years So, the age of father after five years = 3(x + y) + 5 = 3x + 3y + 5 According to the question, 3x + 3y + 5 = 2(x + y + 10) ⇒ 3x + 3y + 5 = 2x + 2y + 20 ⇒ 3x – 2x + 3y – 2y = 20 – 5 ⇒ x + y = 15 So, the age of two children = 15 years And the age of father = 3(15) = 45years Hence, the age of father is 45 years and the age of his two children is 15 years.
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