Question

: A father and his son decide to sum their age. The sum is equal to sixty years. Six years ago the age of the father was five times the age of the son. Six years from now the son’s age will be:

A) 23 years B) 19 years C) 20 years D) 22 years​

Answer 1

Answer:

let the present father's age be x and sons be y years...

SUM OF THEIR AGES..

x+y=60.............1

6 YEARS AGO....

father's age will be (x-6) years

sons age will be. (y-6) years

age of father = 5 times age of son

x-6 = 5(y-6)

x-6 =. 5y-30

x-5y= -24.........2

solving 1 and 2 , we get

x+y=60

x-5y=-24

subtracting, we get

6y=84

y=14 years

therefore ,present age of son is 14 years

after 6 years his age will be

14+6=20 years.

ans

Answer 2

♡ Heya user ♡

Given :-

▪ A father and his son decide to sum their age. The sum is equal to sixty years. Six years ago the age of the father was five times the age of the son.

To Find :-

▪The age of the son after 6 years.

Solution :-

✏According to 1st condition:-

Let the present age of the son be x years

& the father's age is (60-x) years.

✏According to the 2nd condition:-

The age of the father six years ago

= (60-x) -6

= (54-x) years

& the age of the son will be ( x-6) years.

✏As per the question, we have

54 -x = 5(x-6)

➯ 6x =84

➯ x = 14

Hence, the sons age after 6 years

= x+6

= 14+6

= 20 years

So, the correct option is C) 20 years.

✧Thanks ✧