Question

A father and his son decide to sum their age. The sum is equal to sixty years. Six years ago the age of the father was five times the age of the son. Six years from now the son’s age will be:​

Answer 1

Let father's age be “x” and son’s age be “y”

A/q, current age of father and son is 60 years.

I. E. x+y=60…..(i)

6 years ago,

Father's age=(x-6) and son’s age=(y-6)

And, father's age was 5 times of son’s age

I. E. (x-6) = 5(y-6)…. (ii)

= >x-6 = 5y-30

=>5y-x=24

Adding (i) and (ii)

(y+x=60) +(5y-x=24)

=>6y=84

=>y=14

So, son’s present age is 14 years and after 6 years his age will be (14+6)=20years.

katti jao :(

Answer 2

Answer:

Let :

Present Age of father = x years

Present age of son = y years

Given :

Sum of present age of father & son = 60 years

6 years ago , age of father = 5 times age of son

To find:

Age of son after 6 years

Solution :

Case 1)

Sum of present age = 60

x + y = 60 .... equation 1

Case 2)

Age of father , 6 year ago = (x-6)

Age of son, 6 year ago = (y-6)

Now , according to question-

age of father = 5 times age of son

(x-6) = 5(y-6)

x - 6 = 5y - 30

x = 5y - 30 + 6

x = 5y - 24 ..... equation 2

On putting value of x from equation 2 into equation 1, we get;

(5y-24) + y = 60

6y = 60+24

6y = 84

y = 84 ÷ 6

y = 14

Now we need to find age of son after 6 years from now ,

that is , y + 6

Age of son after 6 years from now = 14 + 6

Age of son after 6 years from now = 20 years

ANSWER : 20 years

Step-by-step explanation: