Question

A father and his son decide to sum their age. The sum is equal sixty years. six years ago the age of the father was five times the age of the son Six years from now the son's age will be
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Answer 1

Answer:

20

Step-by-step explanation:

Let the present age of the son be x years

& the father's age is (60-x) years.

The age of the father six years ago

= (60-x) -6

= (54-x) years = father

Son = x-6

54 -x = 5(x-6)

6x =84

x = 14

Son = 20 years as 14 + 6 = 20

thanks

Answer 2

Answer:

Answer :

20 years

Step-by-step explanation :

Let the present age of father be x years

and his son's present age be y years

Father and his son decides to sum their ages. The sum is equal to sixty years

Sum of their ages = 60 years

        x + y = 60

        x = 60 - y  -- eqn [1]

Six years ago,

father's age was = (x - 6) years

his son's age was = (y - 6) years

Given, Six years ago the age of the father was five times the age of the son

 x - 6 = 5(y - 6)

 x - 6 = 5y - 30

 5y - x = 30 - 6

 5y - x = 24

 5y - (60 - y) = 24  [ eqn. [1] ]

 5y - 60 + y = 24

  6y = 24 + 60

  6y = 84

   y = 84/6

   y = 14

The present age of son = 14 years

The present age of father = 60 - 14 = 46 years

After six years,

his son's age will be = 14 + 6 = 20 years

Verification :

Condition - 1 : The sum is equal to sixty years.

     14 + 46 = 60

        60 = 60

       LHS = RHS

Condition - 2 : Six years ago the age of the father was five times the age of the son.

Six years ago,

Father's age = 46 - 6 = 40 years

Son's age = 14 - 6 = 8 years

father's age = 5(son's age)

  40 = 5(8)

   40 = 40

  LHS = RHS

Hence proved!

Step-by-step explanation: