A father and his son decide to sum their age. The sum is equal to sixty years. Six years
ago the age of the father was five times the age of the son. Find their present ages.
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Answer:
Let the present age of son be x.
Then, present age of father is (60−x).
According to the question,
⇒ (60−x)−6=5(x−6)
⇒ 54−x=5x−30
⇒ 54+30=5x+x
⇒ 84=6x
⇒ x=
6
84
⇒ x=14
∴ Son's age after 6 years =(x+6)years
=(14+6)years
=20years.
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