Question

A father and his son decides to sum their age. The sum is equal to sixty years. Six years ago the age of the father was five times the age of the son. Six years from now the son’s age will be?

Answer 1

Answer:

18

Step-by-step explanation:

let age of son be x

age of Father be 5x

and 6 yrs ago

5x - 6+ x - 6= 60

x= 12

TO DETERMINE THE AGE OF SIN AFTER 6 YRS ADD 6 TO HIS PRESENT AGE

Answer 2

Given :

The sum of the ages of father and son is 60 yrs .

Six years ago the age of the father was five times the age of the son.

To Find :

Age of the son after 6 years .

Solution :

$\longmapsto\tt{Let\:the\:son's\:age\:be=x}$

$\longmapsto\tt{Let\:the\:father's\:age\:be=y}$

$\longmapsto\tt{x+y=60-------(1)}$

Before 6 years :

$\longmapsto\tt{Age\:of\:son=x-6}$

$\longmapsto\tt{Age\:of\:father=y-6}$

A.T.Q :

$\longmapsto\tt{y-6=5(x-6)}$

$\longmapsto\tt{y-6=5x-30}$

$\longmapsto\tt{y=5x-30+6}$

$\longmapsto\tt\bf{y=5x-24}$

Putting the value of y in eq. (1) :

$\longmapsto\tt{x+5x-24=60}$

$\longmapsto\tt{6x-24=60}$

$\longmapsto\tt{6x=60+24}$

$\longmapsto\tt{6x=84}$

$\longmapsto\tt{x=\cancel\dfrac{84}{6}}$

$\longmapsto\tt\bf{x=14}$

Therefore :

After 6 years :

$\longmapsto\tt{Age\:of\:son=x+6}$

$\longmapsto\tt{14+6}$

$\longmapsto\tt\bf{20\:yrs}$