Question

A father and his son start
from a point A
with speed of 12km/h and 18km /h respectively
and reach another point B.If
his son starts 60 minutes after
his father from A and reaches
B 60 minutes before his
father, what is the distance
between A and B.​

Answer 1

Answer:

72 km

Step-by-step explanation:

Let distance between A and B be x km

Son's speed = 18 km / hr

18 = x / t Case 1

Father's speed = 12 km/ hr and he takes 2 more hours to reach B than his son.

12 = x / (t + 2) Case 2

From Case 1 and 2,

x = 18t = 12t + 24

18t - 12t = 24

6t = 24

t = 24/6 = 4 hours

x = 18t = 18 x 4 = 72 km

Ans: distance between A and B is 72km