Question

A father can do job as fast as 2 sons working together. if one son does the job in 3 hours and the other in 6 hours, the number of hours taken by the father, to do the job alone is

Answer 1

One hour's work of First son = 1/3
One hour's work of Second son = 1/6

The father can do as fast as both working together >>>>

Father's one hour's work = 1/3 + 1/6
= 3/6
= 1/2

Work done in 1 hour = 1/2
Therefore, Father will take 2 hours to complete the work alone.

ANSWER = 2 HOURS

HOPE IT HELPS :):):)
MARK AS BRAINLIEST