Question

A father divided his property between two sons A and B and one daughter
C. The person has Rs. 80000 in cash, Rs. 5 lakhs as land and Rs. 6 lakhs
as gold. He gave half of the gold to his daughter and remaining gold
divided between sons in equal proportion. He gave only 20% of total land
to his daughter and divided the remaining land betiveen sons A and B in
the ratio of 3 : 1 respectively on the condition that the child who received
highest share of land will give Rs. 2500 per month to his father. He gave
75% of the total cash amount to his daughter and remaining cash amount
was divided between sons in equal proportion.
how much total property (in cash ,land and gold together)did c get?
(A) Rs. 4.9lakhs
(B) Rs 4.6 lakhs
(C) Rs. 4.7 lakhs
(D) Rs. 4.8 lakhs
B​

Answer 1

Answer:

Option (B)

Step-by-step explanation:

Amount given in form of gold = 1/2× 6,00,000 = 3,00,000

Amount given in form of land = 20% of 5,00,000 = 0.2×5,00,000 = 1,00,000

Amount given in form of cash = 75% of 80,000 = 0.75×80,000 = 60,000

TOTAL AMOUNT GIVEN TO DAUGHTER = 3,00,000+1,00,000+60,000

=> 4,60,000

=> 4.6 Lakhs

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Answer 2

Answer:Total property (In cash, land and Gold together) Daughter C got = 4 $lakhs$ 60 thousand = Rs. 4.6 $lakhs$

Step-by-step explanation:

Given:A father divided his property between two sons A and B and one daughter C. The person has Rs. 80000 in cash, Rs. 5 $lakhs$ as land and Rs. 6 $lakhs$ as gold. He gave half of the gold to his daughter and remaining gold divided between sons in equal proportion. He gave only 20% of total land to his daughter and divided the remaining land between sons A and B in the ratio of 3 : 1 respectively on the condition that the child who received highest share of land will give Rs. 2500 per month to his father. He gave 75% of the total cash amount to his daughter and remaining cash amount was divided between sons in equal proportion.

To find: How much total property (in cash, land and Gold together) did C get?

Explanation:

Step 1: It is given that the daughter get half amount of gold ,20% of Rs. 5 $lakhs$ as land and 75% of Rs. 80000 in cash,So,

Total share of daughter C  $=$ $\frac{1}{2}$ × $600000$ + 20% of 500000 + 75% of $80000$

                                             $= 300000 + \frac{20}{100}$ × $500000 + \frac{75}{100}$ × $80000$

                                              $= 300000 + 100000 + 60000$

                                              $= 460000$

                                               $=4.6 Lakhs$

Step 2:Remaining Gold = 6 $lakhs$ – 3 $lakhs$ = 3 $lakhs$

Remaining Land = 5 $lakhs$ – 1 $lakhs$ = 4 $lakhs$

Remaining Cash = 80000 – 60000 = 20000 Rs.

Step 3:The share of son A = $\frac{1}{2}$ of remaining gold + $\frac{3}{4}$ of remaining land + $\frac{1}{2}$ of remaining cash = 1.5 $lakhs$ + 3 $lakhs$ + 10 thousand = 4.6 $lakhs$

Step 4:The share of son B = $\frac{1}{2}$ of remaining gold + $\frac{1}{4}$ of remaining land + $\frac{1}{2}$ of remaining cash = 1.5 $lakhs$ + 1 $lakhs$ + 10 thousand = 2.6 $lakhs$.

Hence. the daughter C get total property  (in cash ,land and gold together) $= 4.6Lakhs$

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Father divides his property among his three sons in the ratio 1 and 1 by 2 is to 2 by 3 is to 3 by 4 find the share of first Son if the total property is 70000​.

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A father divides his estate among his three sons, in such a manner, that:

The first has Rs.10000 less than half of the whole;

The second has Rs.8000 less than one third of the whole;

The third has Rs.6000 less than one fourth of the whole;

What is the value of the estate?

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