A father divides his property among his 3 sons such that eldest son's share is double the second
son's share and the share of the second son is triple the third son's share. If the second son gets Rs.
4000 more that the third, find the value of the total property.
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Answer:
Second son's property = 6000
( 2000 * 3 = 6000, 6000 - 2000 = 4000 )
Third son's property = 2000
( 6000 / 3 = 2000 )
First son's property = 12,000
( 6000 * 2 )
Total property = 12,000 + 6,000 + 4,000
= 22,000
PLEASE MAKE ME A BRAINLIST.
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