A father doubles his son's age if the total age is 49 and the age difference is 31. What is the age of the father and his son?
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Answer:
Consider Father's age as F & son's age as S
F + 2S = 49 …(1)
F - S = 31 …(2)
Multiply (2) * 2
2F - 2S = 62 …(3)
(1) + (3)
3F = 111
F = 37 yrs old
From (2)
S = 37 - 31 = 6 yrs old
Step-by-step explanation:
Answered by
0
Answer:
F + 2S = 49 …(1)
F - S = 31 …(2)
Multiply (2) * 2
2F - 2S = 62 …(3)
(1) + (3)
3F = 111
F = 37 yrs old
From (2)
S = 37 - 31 = 6 yrs old
Step-by-step explanation:
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