Math, asked by Anonymous, 10 months ago

A father has 17 camels and he want to divide these camels among 3 children.

(i) The elder one will get 1/2.
(ii) The middle one will get 1/3.
(iii) The younger one will get 1/4.

Find out the number of camels every child will get ?

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Answers

Answered by Aɾꜱɦ
19

About your Question :-

this question is taken by the story of 17 camels and 3 sons.

Your Answers :-

  • \</u><u>small </u><u>\mathtt{</u><u> </u><u>Eldest</u><u>\</u><u>:</u><u> </u><u>son </u><u>\</u><u>:</u><u>got</u><u>\</u><u>:</u><u> </u><u>9 </u><u>\</u><u>:</u><u>camels</u><u>}

  • \small \mathtt{ Middle \:son\: got \:6 \:camels}

  • \small \mathtt{ Younger\: son\: got\: 2 \:camels}

Step by step explanation by story:-

there was one wise man come to solve the problem of camels. and wise man gave his own camel to him. now camel was 18.

 \rule</strong><strong>{</strong><strong>5</strong><strong>0</strong><strong>}{2} Eldest son:- \rule{50}{2}

The eldest Son got Half the Camels, which Now Counted to 18 / 2 = 9 Camels!

The Eldest one got 9 Camels as his share.

  • the remaining camel was 9.

 \rule{50}{2} Middle son:- \rule{50}{2}

the Second son to Read the will. He Was Assigned 1 / 3 of the Total camels.

It Came to 18 / 3 = 6 Camels.

The second son got 6 camels as his share.

  • total camel shared 6+9=15camel

 \rule{50}{2} Youngest son:- \rule{50}{2}

The Third son read out his Share of camels: 1 / 9th of the total Number of camels – 18 / 9 = 2 camels.

The Youngest one got 2 Camels as his share.

 \rule{50}{2} Now,  \rule{50}{2}

totally there Were 9 + 6 + 2 camels Shared by the brothers, which Counted to 17 camels.

Now the wise man take him his own camel.

The Wise man Solved this problem Smartly with his Intelligence.

✌ᴍᴀᴛʜsᴀʀʏᴀʙʜᴀᴛᴛA✌

#answerwithquality #bal

Answered by Anonymous
4

About your Question :-

this question is taken by the story of “17 camels and 3 sons”.

Your Answers :-

\</u><u>small </u><u>\mathtt{</u><u> </u><u>Eldest</u><u>\</u><u>:</u><u> </u><u>son </u><u>\</u><u>:</u><u>got</u><u>\</u><u>:</u><u> </u><u>9 </u><u>\</u><u>:</u><u>camels</u><u>}

\small \mathtt{ Middle \:son\: got \:6 \:camels}

\small \mathtt{ Younger\: son\: got\: 2 \:camels}

Step by step explanation by story:-

there was one wise man come to solve the problem of camels. and wise man gave his own camel to him. now camel was 18.

\rule</strong><strong>{</strong><strong>5</strong><strong>0</strong><strong>}{2} Eldest son:- \rule{50}{2}

The eldest Son got Half the Camels, which Now Counted to 18 / 2 = 9 Camels!

The Eldest one got 9 Camels as his share.

the remaining camel was 9.

\rule{50}{2} Middle son:- \rule{50}{2}

the Second son to Read the will. He Was Assigned 1 / 3 of the Total camels.

It Came to 18 / 3 = 6 Camels.

The second son got 6 camels as his share.

total camel shared 6+9=15camel

\rule{50}{2} Youngest son:- \rule{50}{2}

The Third son read out his Share of camels: 1 / 9th of the total Number of camels – 18 / 9 = 2 camels.

The Youngest one got 2 Camels as his share.

\rule{50}{2} Now, \rule{50}{2}

totally there Were 9 + 6 + 2 camels Shared by the brothers, which Counted to 17 camels.

Now the wise man take him his own camel.

The Wise man Solved this problem Smartly with his Intelligence.

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